First, to make this a bit easier, we can turn the fractions into decimals.
1/2 = 0.5 , 3 1/2 = 3.5
Divide 3.5 by 0.5.
3.5 ÷ 0.5 = 7
<h2>Answer: </h2>
<u>The factory made </u><u>7 batches of cookies</u><u>.</u>
Answer:
= x^4 -x^3 -4x^2 -3
Step-by-step explanation:
f(x) = x^4 -x^2 +9
g(x) = x^3 +3x^2 +12
We want to find f-g
(f-g) (x) = x^4 -x^2 +9 - (x^3 +3x^2 +12)
Distribute the minus sign
(f-g) (x) = x^4 -x^2 +9 - x^3 -3x^2 -12
= x^4 -x^3 -4x^2 -3
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
x + 18 ≥ 26
Step-by-step explanation:
"greater than or equals": ≥
x + 18 ≥ 26 is your answer.
If you are trying to solve it so you isolate x, subtract 18 from both sides:
x + 18 (-18) ≥ 26 (-18)
x ≥ 26 - 18
x ≥ 8
x ≥ 8 is your answer.
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