Choice-'B' is the correct choice . . . 2E9A .
I began converting the original numbers to decimal (base 10),
but decided that 5 points are not worth that much aggravation.
At that point, I wondered whether I could just write it down and
do it like any old other subtraction exercise. I've never done
that before with hex numbers, but I found that I could !
The only place you have to be extra careful is in the third place,
where you have to subtract '9' from '2'. In order to do that, you
have to borrow one from the 'F'. That makes the 'F' an 'E', and
it makes the '2' an '18', from which you can then easily subtract
the '9'. The difference of '2E9A' then jumps right out.
Thank you. I never knew you could just do that.
Answer:
Yes, it is a function
Step-by-step explanation:
the definition of a function is "a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output." Our input is represented by x, or the first number in the parentheses, and our output is y, or the second number in the parentheses. Because each x value had exactly one output, or y, it is a function
Answer:
a) 3/64 = 0.046 (4.6%)
b) 63/64 = 0.9843 (98.43%)
c) 1/64 = 0.015 (1.5%)
d) 1/4 = 0.25 (25%)
Step-by-step explanation:
in order to verify that the f(x) is a probability mass function , then it should comply the requirement that the sum of probabilities over the entire space of x is equal to 1. Then
∑f(x)*Δx = 1
if f(x)=(3/4)(1/4)^x , x = 0, 1, 2, ...
then Δx=1 and
∑f(x) = (3/4)∑(1/4)^x = (3/4)* [ 1/(1-1/4)] = (3/4)*(4/3) = 1
then f represents a probability mass function
a) P(X = 2)= f(x=2) = (3/4)(1/4)^2 = 3/64 = 0.046 (4.6%)
b) P(X ≤ 2) = ∑f(x) = f(x=0)+ f(x=1) + f(x=2) = (3/4) + (3/4)(1/4) + 3/64 = 63/64 = 0.9843 (98.43%)
c) P(X > 2)= 1- P(X ≤ 2) = 1 - 63/64 = 1/64 = 0.015 (1.5%)
d) P(X ≥ 1) = 1 - P(X < 1) = 1 - f(x=0) = 1- 3/4 = 1/4 = 0.25 (25%)
The third equation is correct.
