Let's call the width: w

the lenght is then 3w+4 ("4 more than 3 times the width")

and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.

this is also equal to 18.4:

8w+8=18.4
8w=10.4
w=1.3

this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9

and the area is their product:
1.3*7.9=10.27

6 0

3 years ago

The function of f(x) = 3x + 2 has a domain of -3 < x < 5. What is the domain of f-1(x)?

Flura [38]

<h3>Answer: -7 < x < 17</h3>

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Explanation:

Plug in the lower bound of the domain, which is x = -3

f(x) = 3x+2

f(-3) = 3(-3)+2

f(-3) = -9+2

f(-3) = -7

If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.

If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.

The range of f(x) is -7 < y < 17

Recall that the domain and range swap places when going from the original function f(x) to the inverse $f^{-1}(x)$

This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.

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In short, we found the range of f(x) is -7 < y < 17.

That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.

6 0

3 years ago