your answer would be
2/5, 3/7, 3/5, 1/2
Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Answer:
3rd option (top right)
Step-by-step explanation:
3rd option represents a linear equation
y = -2x-1
Answered by GAUTHMATH
Answer:
9 1/6 miles
Step-by-step explanation:
Add the mixed number by the improper fraction.
1 + 1/3 + 35/6
Solve the fractions first.
In order to have both of the fractions have the same denominator, find the Least Common Multiple of both of the fractions.
1/3 = 2/6
2/6 + 35/6 = 37/6
Turn the improper fraction into a mixed number by dividing the the numerator by the denominator. When you get your quotient, use the remainder as the new numerator over the denominator.
37/6 = 6 1/6
Now, add the 1.
6 1/6 + 1 = 7 1/6
Now, add the 2 miles that Carol walked on Wednesday.
7 1/6 + 2 = 9 1/6
So, Carol walked about 9 1/6 miles on Monday, Tuesday, and Wednesday all together.