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4 years ago

-25+4h=50.25 solve for h

Mathematics

2 answers:

Harlamova29_29 [7]4 years ago

7 0

Answer:

h=18.81

Step-by-step explanation:

First thing you have to do is add 25 to 50.25 which gets you 74.25

4h=74.25

next divide 74.25/4 which get you 18.81

18.81 is your answer

Murrr4er [49]4 years ago

3 0

Hi There!

Step-by-step explanation:

Solve for h,

-25 + 4h = 50.25

Simplify,

25 - 4h = 50.25

Add 25 to both sides,

25 - 4h + 25 = 50.25 + 25

Simplify,

4h = 25.25

Divide both sides by 4,

4h/4 = 25.25/4

Simplify,

h = 18.8125

Answer:

h = 18.8125

Hope This Helps :)

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By closure property of multiplication and addition of integers,

If $x + \dfrac{1}{x}$ is an integer

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From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

$x + \dfrac{1}{x}$

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}$

By simplification of the cube of the given integer expressions, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$

Therefore, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}$

By rearranging, we get;

$x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )$

Given that $x + \dfrac{1}{x}$ is an integer, from the closure property, the product of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3$ is an integer and $3\cdot \left (x + \dfrac{1}{x} \right )$ is also an integer

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$\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

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3 years ago

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Romashka [77]

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