Formula for the axis of symmetry ( or x-coordinate of the vertex ):
x = -b / 2a
2 = -(-8) /2 a
2 = 8 / 2a
2 a = 4
Answer: a = 2
Answer:
Step-by-step explanation:
<u>Step 1: Find the standard form of the equation</u>
The equation that was given made no sense so I will recreate the entire equation using the point slope formula.
<u>Use the point slope formula</u>
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<u>Find the slope</u>
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<u>Combine them together</u>
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<u>Convert to standard form</u>
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Answer:
Answer:
see explanation
Step-by-step explanation:
(a + b)²
= (a + b)(a + b)
Each term in the second factor is multiplied by each term in the first factor, that is
a(a + b) + b(a + b) ← distribute parenthesis
= a² + ab + ab + b² ← collect like terms
= a² + 2ab + b²
I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
c
I think that it is
Step-by-step explanation:
sorry if am not right