Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
Answer:
55°
Step-by-step explanation:
Let the centre of the circle be C
mFG=110 (It's hard to read but I assume thats what the 110 marks)
mFG=<FCG=110
Consider ΔFCG (an isosceles triangle since CF=CG=radius). Angles in a triangle add to 180 and <CFG=<CGF so <CFG=(1/2)(180-110)=(1/2)(70)=35°
<EFG+<CFG=90
<EFG+35=90
<EFG=55°
Answer:
0=-5 FALSE
Step-by-step explanation:
5+4d+2=9d+2-5d is false
Answer: 5/-12
Explanation
Divide both the denominator and the numerator by -5 to obtain the denominator of -12 and the numerator of 5.
5/-12
Hope this helps :)