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gladu [14]
3 years ago
7

Please help asap! Will give brainliest! Please answer correctly! No guessing. Check all that apply.

Mathematics
2 answers:
bearhunter [10]3 years ago
6 0

Answer:F

Step-by-step explanation:

xxMikexx [17]3 years ago
4 0

Answer:

i honestly think that its A, C, D, F.

Step-by-step explanation:

for the A i think that you need to write down the facts so you dont forget and you remember when someone asks you a question.

For C you should gather your resources so you can do the experiment again if your not satisfied with the first result.

For D you should draw a diagram so you can keep track of your information that you used to get the final solution.

For F, you should always make sure that you didn't mess up and that you can redo it to double check.

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Larissa is considering two summer jobs. A job at the mall pays $400 per week plus $15 for every hour of overtime. A job at the m
Rina8888 [55]
Solve using system of equations!
Let y=total amount of money and x=hours of overtime.
mall: y=400+15x
movies: y=360+20x
Solve! Set the equations equal to each other to find x.
400+15x=360+20x
40=5x
x=8
After 8 hours of overtime the movies would pay her more.
4 0
3 years ago
A doctor is measuring the mean systolic blood pressure of female students at a large college. Systolic blood pressure is known t
Nana76 [90]

Answer:

The correct option is (b).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times\frac{SD}{\sqrt{n}}

The confidence interval for population mean can be computed using either the <em>z</em>-interval or <em>t</em>-interval.

The <em>t</em>-interval is used if the following conditions are satisfied:

  • The population standard deviation is not known
  • The sample size is large enough
  • The population from which the sample is selected is normally distributed.

For computing a (1 - <em>α</em>)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.<em>n</em> < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.

In this case the sample size is, <em>n</em> = 28 < 30.

Also it is provided that the systolic blood pressure is known to have a skewed distribution.

Since the sample is small and the population is not normally distributed, the  sampling distribution of sample mean will not be approximated by the normal distribution.

Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.

The correct option is (b).

5 0
2 years ago
A triangle has angles measuring 58 and 93 degrees. What is the measure of the third angle?
wolverine [178]
The third angle is 29 degrees.

180 - 58 - 93 = 29
8 0
2 years ago
Evaluate 6+x6+x6, plus, x when x=3?
vampirchik [111]

Answer:

42

Step-by-step explanation:

x=3

6+x6+x6

6+(3)6+(3)6

6=6

(3)6=18

(3)6=18

6+18+18

24+18

42

Hope this helps ;) ❤❤❤

8 0
3 years ago
Read 2 more answers
Mr. Ramsey just finished bathing his kids, and now he is draining the tub. The tub contains 32 gallons of water and is draining
KIM [24]
The answer would be 11 gallons.

The tub starts with 32 gallons. Every minute it loses 3 gallons.

So after 1 minute it has lost 3 gallons. For example:
32-3= 29 Meaning that after 1 minute the tub has 29 gallons left.

Now you have to remember that the tub is draining for 7 minutes. So it is losing 3 gallons 7 times, because it loses 3 gallons each minute and there are 7 minutes.

We can use multiplication to find how many gallons the tub loses after 7 minutes. This sign “X” basically means “groups of”. We have 7 groups of 3, or
7 X 3

This is the same as saying we have 3, 7 times. Written like this:

3+3 +3 +3 +3 +3 +3 = 21

So after 7 minutes the tub has lost 21 gallons.

Now we take the original number of gallons and take away what was lost:

32-21=11

So there are 11 gallons left after 7 minutes.

Please let me know if you need any further explanation. Hope this helped.

7 0
2 years ago
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