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Rina8888 [55]
3 years ago
13

Which strategies can be used to solve this problem?

Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0
Your answers are both a and b. They have a more logical procedure to dividing the people at their tables. C isn't completing the left over people to their tables. D isn't providing enough info and isn't very reasonable. Hope this helps :)
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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
1. Using the slope-intercept form of a line, find the equation of the line with slope and y-intercept –2. Then graph the line on
solmaris [256]
To find the x-intercept, throw in 0 for y:



So the x-intercept is (2,0).

To find the y-intercept, throw in 0 for x:



So the y-intercept is .
8 0
3 years ago
In 1945, gasoline cost an average of $0.15/gal. By 2015, the average cost of gasoline had increased 1500%. What was the average
Murrr4er [49]
.15*15=15^2/100=$2.25/gal
7 0
3 years ago
PLEASE HELP!!!!!!!!!
pychu [463]
We let
x as the bushels of apples used to make apple cider
y as the bushels of apples used to make apple juice

The system of equations is
x + y = 18
20x + 15y = 330

Solving for x and y
x = 12
y = 6

12 bushels of apples are needed to produce apple cider
6 bushels of apples are needed to produce apple juice<span />
8 0
3 years ago
What is the length of the line?
Ganezh [65]
The rise over run is 1/6
4 0
3 years ago
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