Looks like the given limit is

With some simple algebra, we can rewrite

then distribute the limit over the product,

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.
For the second limit, recall the definition of the constant, <em>e</em> :

To make our limit resemble this one more closely, make a substitution; replace 9/(<em>n</em> - 9) with 1/<em>m</em>, so that

From the relation 9<em>m</em> = <em>n</em> - 9, we see that <em>m</em> also approaches infinity as <em>n</em> approaches infinity. So, the second limit is rewritten as

Now we apply some more properties of multiplication and limits:

So, the overall limit is indeed 0:

<span>His previous balance was $321.14
289.14 + 32 = 321.14
hope this helps
</span>
Answer:
214
Step-by-step explanation:
The set up would be x + (x + 1) + (x + 2) + (x + 3) = 854, naturally as the numbers are consecutive. Solving for x:
x + (x + 1) + (x + 2) + (x + 3) = 854,
x + x + 1 + x + 2 + x + 3 = 854,
4x + 1 + 2 + 3 = 854,
4x + 6 = 854,
4x = 854 - 6 = 848,
x = 848/4 = 212
The third number then should be 212 + 2 = 214
5x+1(6-4) = +1(5x6)-(5x)
this would be a hard question to answer but i think i can do it ((( nNOTTTT))))
The answer to that is 80 percent as a fraction is 8/10