Set up a system of equations:
2l + 2w = 72
l = 2w
Solve the system using substitution:
2(2w) + 2w = 72
Solve for w:
4w + 2w = 72
—> 6w = 72
—> w = 12
Plug in the value for ‘w’ in the second equation:
l = 2(12)
—> l = 24
The width is 12.
The length is 24.
I think that equation is supposed to look like this:
The reason I say that is because this is an exponential decay problem, with a starting amount of 50 pieces of candy.
If that's the case, then it would look like this with a t value of 5:
and
so the amount of candy left after 5 minutes is 16.384 or 16
To solve for the midpoint of the segment we use the equation that is given as:
(x1 + x2 / 2) , (y1 + y2 / 2)
For the points given,
(x1 + x2 / 2) , (y1 + y2 / 2)
(3+ 2 / 2) , (-5 + 9 / 2)
(5/2 , 2) or (2.5 , 2)
Hope this answers the question. Have a nice day. Feel free to ask more questions.
So we need to know the likelihood for each sum. the first sum is 2, and there is no way for one of the die to equal 6 if the sum is 2, therefore the probability is 0. The same applies when the sum is 3, 4, 5, and 6. Once the sum gets to 7, you must evaluate all possible options.
For 7, your options are 1&6, 2&5, 3&4, 4&3, 5&2, 6&1, where the number before the ampersand is the first die, and the number after is the second. there is only one option of the 6 choices where the first die is 6, therefore the probability is 1/6.
For 8, the options are 2&6, 3&5, 4&4, 5&3, 6&2. so of the 5 choices, there is only one option, therefore the probability is 1/5.
For 9, the choices are 3&6, 4&5, 5&4, 6&3. So of the 4 choices, there is 1 option, therefore the probability is 1/4.
For 10, the options are 4&6, 5&5, 6&4. Of the 3 choices, there is 1 option, therefore the probability is 1/3.
For 11, the options are 5&6, 6&5. Of the 2 choices, there is 1 option, therefore the probability is 1/2.
Finally, for 12, the only option is 6&6. There is only one choice, so the probability is 1.
The cutoff will be evaluated as follows:
let the cutoff be x
but
P(x>0.01)=1-P(x<0.01)=1-0.01=0.99
the z value corresponding to 0.99% is z=2.33
thus
2.33=(x-600)/60
solving for x we get:
139.8=x-600
x=739.8
