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Komok [63]
3 years ago
12

The base of a parallelogram with the area (A) of 72 square inches and height (H) of 6 inches.

Mathematics
1 answer:
Elza [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Let's make a simple equation! It's much, much simpler than you think. Let's look closely.

<h3>Area = Base x Height</h3>

We already know the area, so we can substitute this already.

<h3>72 = Base x Height</h3>

We also know the height, 6.

<h3>72 = Base x 6</h3>

We can now replace "base" as x to make it simpler to solve the equation we made!

<h3>6x = 72</h3><h3>x = 12</h3><h3 /><h2>The base of the parallelogram is 12 inches.</h2>
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hudson went into a restaurant and bought 8 hamburgers and 4 drinks, costing a total of $52. Levi went into the same restaurant a
katrin [286]

Answer:

The price of each hamburger is $5 and the price of each drink is $3.

Step-by-step explanation:

  • x --> the price of each hamburger
  • y --> the price of each drink
  • 8x+4y=52
  • 5x+7y=46
  • Solve system of equations
  • The intersection is (3,5)

4 0
3 years ago
Find exact value of cos
mylen [45]
<h3>Answer: Choice B. \frac{\sqrt{91}}{10}</h3>

Work Shown:

\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\

7 0
3 years ago
Read 2 more answers
1 &gt; 5m+ 3 What does m equal?
mote1985 [20]

Answer:

Step-by-step explanation:

1 > 5m+ 3

Value of  5m+ 3 should be less than 1.

So value of m can be m<= -1

If m = -1;  5m+ 3 = 5*-1 +3 = -5 + 3 = -2 <1

5 0
3 years ago
2d= a-b/b-c solve for a
Alex_Xolod [135]
<span>2d= a-b/b-c solve for a

Okie, you mean: 2d=a-b:(b-c)
If that, we have a= 2d+b:(b-c)
Done!</span>
6 0
3 years ago
Mumy rien
Furkat [3]

Answer:

h=12.5\ in

Step-by-step explanation:

we know that

The surface area of a square prism is given by the formula

SA=2(b^2)+4bh

where

b is the length side of the square base

h is the height of the prism

we have

b=5\ in\\SA=300\ in^2

substitute

300=2(5^2)+4(5)h

solve for h

300=50+20h\\20h=300-50\\20h=250\\h=12.5\ in

3 0
3 years ago
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