Answer:
f=82.4
Step-by-step explanation:
f=9c/5+32
f=9x28/5+32
f=252/5+32
f=50.4+32
f=82.4
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
E^3t=100
ln100=3t
t=(ln100)/3
Simple just subtract and u get-74.85
I think the answer for your question is B
