To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
The margin of error for the 94% confidence interval is 0.6154.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:
The margin of error of this interval is:
The critical value of <em>z</em> for 94% confidence level is, <em>z</em> = 1.88.
Compute the margin of error for the 94% confidence interval as follows:
Thus, the margin of error for the 94% confidence interval is 0.6154.
Then one pencil costs about 2.14 cents.
<span>Entonces un lápiz cuesta alrededor de 2.14 centavos.</span>
Answer:
The loose sweets at ?0.89 for 100 g.
Step-by-step explanation:
First, calculate the price per gram. You do this by dividing the price by the grams.
?1.49 / 120 g = 1.49 / 120 = 0.0124 (4 dp)
Because the answer was very long, I have rounded it to 4 decimal places (4 dp).
?0.89 / 100 g = 0.89 / 100 = 0.0089
Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.
0.0124 x 100 = 1.24
0.0089 x 100 = 0.89
Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.
That is sudoku, a game that I am really good at. first off the square on the left in the middle is messed up, because on the square above it there is a 5 where it would make the 5 in the middle left square incorrect. So you have to erase the 5 in the square on the middle left. Then if you can do sudoku, you could do the rest.
hope I helped!
