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3 years ago

Diego also adds 28 tablespoons of sugar. How many cups did he use?

Mathematics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

The answer is C.

Step-by-step explanation:

1.) There are 16 tablespoons in 1 cup.

2.) Divide 28 tablespoons by 16 tablespoons, and receive the answer 1.75.

3.) 1.75 converted into fraction form is 1 AND 3/4 cups of sugar.

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Solve -4x ≥ -8. Graph the solution.

Semmy [17]

Answer:

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Step-by-step explanation:

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3 years ago

Three apple pies, all the following shape, are left on a counter. How much total pie has been left?

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3 years ago

What time is 5 3/4 hours after 11:32 pm?<br> Please show work, thank you.

poizon [28]

we have to first convert fraction of hours into minutes

1 hour is equivalent to 60 minutes

then 3/4 hour is - 3/4 of 60

when the of function is used we have to multiply the 2 numbers

then $\frac{3}{4} * 60 = \frac{3*60}{4} = \frac{180}{4} = 45$

3/4 of an hour is equivalent to 45 minutes

then we have to add 5 hours and 45 minutes to 11.32 pm

add 5.45 to 11.32

11.32

5.45 +

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16.77

then its 16 hours and 77 minutes

an hour has only 60 minutes so we subtract 60 minutes from 77 minutes and add that hour to 16 hours

16 hours + 1 = 17 hours

77 minutes - 60 minutes = 17 minutes

17 hours 17 minutes

time is given in pm therefore its a 12 hour clock

so we have to subtract 12 hours from 17 hours 17 minutes

17.17 hours - 12 hours = 5.17

the new time is 5.17 am of the next day

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3 years ago

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Step-by-step explanation:

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Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

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3 years ago