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3 years ago

What's the answer to(3+2)x4²

Mathematics

1 answer:

MAXImum [283]3 years ago

7 0

Answer:

Step-by-step explanation:

you do 3+2 first which is 5. And then you do 4^2 which is 16. when you multiply them you get 80

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You deposit $5000 in an account earning 2% interest compounded monthly. How much will you have in the account in 10 years?

sineoko [7]

Answer:

6000 dollars

Step-by-step explanation:

yadda yadda yadda that is the answer

4 0

3 years ago

What is the quotient of 6/7 divided by 3/14

bija089 [108]

Answer:

6/7 ÷ 3/14

= 6/7 × 14/3

= 2/7 × 14 (we cancelled 3 with 6)

= 2×2 (we cancelled 7 with 14)

= 4

hope it helps

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone help me please!!!

Andre45 [30]

Answer: 3

Explanation:

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 (there are 224 of the 9's)

Thus, N + 1 = 2999...999 + 1 (there are 224 of the 9's)

= 3000...000 (there are 224 of the 0's)

The sum of the digits is: 3 + 0 + ... + 0 (there are 224 of the 0's)

= 3

6 0

3 years ago

Claudio needs to simplify the expression below.

Dmitrij [34]

All purpose calc.com one with the words on the web with a smiley calc type only the problem in no words

8 0

3 years ago

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by: