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Karo-lina-s [1.5K]
3 years ago
13

Please find the value?

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer:

Step-by-step explanation:

By the marks on the angles of this triangle, it is isosceles.  By the Isosceles Triangle Theorem, if 2 angles of a triangle have the exact same measure, then the sides across from those angles have the exact same measure as well.  That means that, algebraically,

5x - 2 = 33 and

5x = 35 so

x = 7

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Step-by-step explanation:

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3 years ago
A thermometer is taken from a room where the temperature is 20◦C to the
lord [1]

Answer:

a) T(2) = 8.265: at time t = 2 minutes the temperature will be 8.265 degress

b) 6 = T(3.55): the temperature will be 6 degrees at time t = 3.55 minutes.

Step-by-step explanation:

When dealing with temperature changes, it's best to work with Newton's Law of Cooling.

T(t) = T_s + Ce^{kt}

here:

T(t) : the temperature in the room.

T_s : ambient (or outdoor) temperature (that always remains constant, in our case: T_s = 5 )

C\,\text{and}\,k: are constants

Our conditions are provided:

1) T(0) = 20

2) T(1) = 12

using the first condition

T(0) = 5 + Ce^{k(0)}\\20 = 5 + C(1)\\C = 15

using the second condition:

T(1) = 5 + Ce^{k(1)}\\12 = 5 + Ce^{k}\\e^k = \dfrac{7}{C}

we can use our calculated value of C to find k

e^k = \dfrac{7}{15}\\k = \ln{(\dfrac{7}{15})}\\k = -0.7621

Finally we can put these constants back in the main equation:

T(t) = T_s + Ce^{kt}

T(t) = 5 + 15e^{-0.7621t} or T(t) = 5 + 15e^{\ln{(\frac{7}{15})t}

a) Reading after one more minute?

so it's asking:

T(2) = ?

T(2) = 5 + 15e^{\ln{(\frac{7}{15})(2)}}\\T(2) = \dfrac{124}{15} \approx 8.267

Hence, after one more minute the temperature of the room will be 8.267 degrees

b) When will it be 6 degrees?

T(t) = 6?

6 = 5 + 15e^{-0.7621t}\\\text{and solve for $t$}\\\\\dfrac{6-5}{15}=e^{\ln{(\frac{7}{15})}t}\\\ln{\left(\dfrac{1}{15}\right)} = \ln{\left(\dfrac{7}{15}\right)t}\\\ln{\left(\dfrac{1}{15}\right)} \div \ln{\left(\dfrac{7}{15}\right)} = t \approx 3.55\\

Hence at t = 3.55 minutes the temperature of the room will be 6 degrees.

8 0
3 years ago
The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

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