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Tom [10]
3 years ago
15

Find the least common multiple of 3 and 7

Mathematics
2 answers:
Sav [38]3 years ago
8 0

The LCM of two prime numbers is generally just their product, since they share no common factors.


3 and 7 are both prime numbers, so their LCM (least common multiple) is simply the numbers multiplied together. In this case, the LCM is thus 21.

Arada [10]3 years ago
3 0

Answer: 21

Step-by-step explanation: To find the least common multiple or <em>lcm</em> of 3 and 7, begin by finding the first few multiples of each number and comparing the lists.

<u><em>Multiples of 3</em></u>

1 × 3 = 3

2 × 3 = 6

3 × 3 = 9

4 × 3 = 12

5 × 3 = 15

6 × 3 = 18

7 × 3 = 21

<em><u>Multiples of 7</u></em>

1 × 7 = 7

2 × 7 = 14

3 × 7 = 21

Since 21 appears in both lists, we can stop here.

Therefore, the least common multiple of 3 and 7 is 21.

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If the point x,y is on the y-axis which of the following is true x=0 y=0​
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Hi there!

Answer:

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<u><em>How it works:</em></u>

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4 0
3 years ago
Three odd-shaped blocks of chocolate have the following masses and center-of-mass coordinates: (1) 0.310kg , ( 0.200 m, 0.320m )
Katarina [22]

Answer:

The x coordinate is 0.047m while y coordinate is 0.081 m

Step-by-step explanation:

The coordinates of the center of the mass of the system are given as follows

x_c=\dfrac{\sum_{i=1}x_im_i}{\sum_{i=1}m_i}\\y_c=\dfrac{\sum_{i=1}y_im_i}{\sum_{i=1}m_i}

So from the data

m1=0.310, x1=0.20,y1=0.320

m2=0.410,x2=0.110,y2=-0.380

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Now by substitution of the values in the above equation

x_c=\dfrac{\sum_{i=1}x_im_i}{\sum_{i=1}m_i}\\x_c=\dfrac{x_1m_1+x_2m_2+x_3m_3}{m_1+m_2+m_3}\\x_c=\dfrac{0.310*0.2+0.410*.110+0.210*-0.3}{0.310+0.410+0.210}\\x_c=0.047m\\\\\\y_c=\dfrac{\sum_{i=1}y_im_i}{\sum_{i=1}m_i}\\y_c=\dfrac{y_1m_1+y_2m_2+y_3m_3}{m_1+m_2+m_3}\\y_c=\dfrac{0.310*0.320+0.410*-0.380+0.210*.630}{0.310+0.410+0.210}\\y_c=0.081m

So the x coordinate is 0.047m while y coordinate is 0.081 m

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