Change each of the fractions into decimals.
1/8 becomes 0.125
-1/7 becomes -0.143
and -0.02555
0.2
In order from least to greatest,
-0.143, -0.02555, 0.125, 0.2
OR
-1/7, -0.02555, 1/8 and 0.2
<u>Answer-</u>
<em>Perimeter of the kite is </em><em>16.2 units</em>
<u>Solution-</u>
As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY
So, perimeter of the kite WXYZ is,
![=2(\overline{WX}+\overline{WZ})](https://tex.z-dn.net/?f=%3D2%28%5Coverline%7BWX%7D%2B%5Coverline%7BWZ%7D%29)
And
![\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}](https://tex.z-dn.net/?f=%5Coverline%7BWX%7D%3D%5Csqrt%7B%281-3%29%5E2%2B%281-4%29%5E2%7D%3D%5Csqrt%7B%28-2%29%5E2%2B%28-3%29%5E2%7D%3D%5Csqrt%7B4%2B9%7D%3D%5Csqrt%7B13%7D)
![\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}](https://tex.z-dn.net/?f=%5Coverline%7BWZ%7D%3D%5Csqrt%7B%281-3%29%5E2%2B%281%2B3%29%5E2%7D%3D%5Csqrt%7B%28-2%29%5E2%2B%284%29%5E2%7D%3D%5Csqrt%7B4%2B16%7D%3D%5Csqrt%7B20%7D)
So, perimeter will be,
![P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units](https://tex.z-dn.net/?f=P%3D2%28%5Csqrt%7B13%7D%2B%5Csqrt%7B20%7D%29%3D16.15%5Capprox%2016.2%5C%20units)
Answer:
its B
Step-by-step explanation:
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or
(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
I uploaded the answer to a file hosting. Here's link:
linkcutter.ga/gyko