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3 years ago

Hector ' s age is 4 less than a number x. Hector is 12 years old. Find the number.

Mathematics

1 answer:

In-s [12.5K]3 years ago

3 0

12+4 =x so you would add 12=4 to get 16. or x=16

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olga2289 [7]

The answer without a doubt is 69/420

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3 years ago

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Vilka [71]

Answer:

The answer is C.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5

emmasim [6.3K]

Answer: $\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$ Explanation:

The given addition exercise is:

$\frac{2}{5}+\frac{1}{3}$

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

$\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}$

Multiply 1/3 by 5/5

$\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}$

The addition becomes

$\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

Therefore, we can fill in the vacant boxes as shown below:

$\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}$

4 0

1 year ago

10)

Oxana [17]

Answer:

I think it is 2 hours

Step-by-step explanation:

because if you have a whole 3 more hours of work you will get 900 bricks layd and if you minus a hour it might be free srry if it is wrong im kinda dumb

8 0

3 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

3 years ago