Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
Answer:
10 blocks
Step-by-step explanation:
Given
east
Required
Determine the shortest possible distance
To better explain my solution, I've added an attachment that illustrates her movement.
Using the attachment as a point of reference, the shortest distance is calculated by calculating the length of the hypotenuse using Pythagoras theorem.
So, we have:
Take positive square root of both sides
Answer:
i have no idea sorry =(
Step-by-step explanation:
<u>Explanation:</u>
<em>Remember, </em>any network security system that constantly monitors a network infrastructure in other to detect and prevent threats to the network is called an intrusion prevention system (IPS.
Many experts agree that a major advantage of waiting until the intrusion system <em>has all the information</em> it needs is that it would allow for easy sensing of a packet drop that can stop the trigger packet.
