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3 years ago

Q(a+y)=67y+93 solve for y

2 answers:

6 0

$Q(a+y)=67y+93\\
aQ+Qy=67y+93\\
Qy-67y=-aQ+93\\
y(Q-67)=-aQ+93\\
y=\dfrac{-aQ+93}{Q-67}\\
\boxed{y=-\dfrac{aQ-93}{Q-67}}$

Grace [21]3 years ago

6 0

Answer:

y=93-aq/q-6

Step-by-step explanation:

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Approximate the square root of 44 to the nearest tenth

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Step-by-step explanation:

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2 years ago

Use the definition mtan=lim

Leokris [45]

(a) mtan refers to the slope of the tangent line. Given f(x) = 9 + 7x ², compute the difference quotient:

$\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h$

Then as h approaches 0 - bearing in mind that we're specifically considering h near 0, and not h = 0 - we can eliminate the factor of h in the numerator and denominator, so that

$m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x$

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2 years ago