4 years ago

Q(a+y)=67y+93 solve for y

2 answers:

6 0

$Q(a+y)=67y+93\\
aQ+Qy=67y+93\\
Qy-67y=-aQ+93\\
y(Q-67)=-aQ+93\\
y=\dfrac{-aQ+93}{Q-67}\\
\boxed{y=-\dfrac{aQ-93}{Q-67}}$

Grace [21]4 years ago

6 0

Answer:

y=93-aq/q-6

Step-by-step explanation:

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