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Maslowich
3 years ago
8

Q(a+y)=67y+93 solve for y

Mathematics
2 answers:
sasho [114]3 years ago
6 0
Q(a+y)=67y+93\\
aQ+Qy=67y+93\\
Qy-67y=-aQ+93\\
y(Q-67)=-aQ+93\\
y=\dfrac{-aQ+93}{Q-67}\\
\boxed{y=-\dfrac{aQ-93}{Q-67}}
Grace [21]3 years ago
6 0

Answer:

y=93-aq/q-6

Step-by-step explanation:

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