Answer:
A. 106 + 2x + 50 = 180
Step-by-step explanation:
A. 106 + 2x + 50 = 180. Correct.
B. 2x + 50 = 180. Incorrect. Angle is not a Straight Angle.
C. 2x + 50 = 106. Incorrect. That equals the first angle.
hope this helps.
Answer:
Pies=$0.85
Donuts= $1.20
Step-by-step explanation:
In the equation let p stand for the number of pies and d stand for the number of donuts.
To solve this set up 2 equations, one representing bill and the other representing Mary Ann.
- Bill's equation is 5p+7d=$12.65.
- Mary Ann's equation is 6p+6d=$12.30
Then solve using a system of equations. Systems of equations can be solved using elimination or substitution. I will use substitution. Solve bill's equation for p. This gives you 
. Then, you can substitute that into Mary Ann's equation. This looks like 
. Solve for d. Once you solve d=1.20. Finally, substitute 1.20 back into either Bill's or Mary Ann's for d and solve for p. No matter which equation you use p=0.85.
Answer:
500
Step-By-Step Explanation:
200/50 = 4
4 * 17 = 68
68 / 2 = 34
34 x 5 = 170
170 / 17 = 10
10 x 50 = 500
Answer:
i think a
Step-by-step explanation:
i'm not sure
Answer:
512
Step-by-step explanation:
Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7
.
For instance, if I divide the set into parts {1,2,4}
and {3,5}, the first part adds up to 7, and its complement adds up to 8
.
Once one makes that observation, the rest of the proof is straightforward. There are 25=32
different subsets of this set (including itself and the empty set). For each one, either its sum, or its complement's sum (but not both), must be ≥8. Since exactly half of the subsets have sum ≥8, the number of such subsets is 32/2, or 16.
