-4x/7>10 choose the solution set.

A particular security's default risk premium is 2 percent. for all securities, the inflation risk premium is 1.75 percent and th

larisa [96]

To solve this problem and calculate the security's equilibrium rate of return, you should sum the security's default risk premium (2.00%), the inflation risk premium (1.75%), the real risk-free rate (3.50%), the security's liquidity risk premium (0.25%) and the maturity risk premium (0.85%). So, you have:

ij*=2.00%+1.75%+3.50%+0.25%+0.85%
 ij*=8.35%

6 0

3 years ago

The tire franks bike moves 75 inches in at one rotation how many rotations will the tire have made after frank rides 50 feet

nexus9112 [7]

8
75 in. = 6.25 ft.
50 ft ÷6.25 = 8

5 0

3 years ago

The ground temperature at an airport is 13 °C. The temperature decreases by 7 °C for every increase of 1 kilometer above the gro

drek231 [11]

I’m guessing it’s -22

4 0

3 years ago

monica tiene 6/10kg de dulces con los cuales llena 1/4 de una bolsa de celofn ¿cual es la capacidad de la bolsa?

Anit [1.1K]

The question in English
Monica has 6 /10 kg of candy with which she fills 1/4 of a cellophane bag. What is the capacity of the bag?

we know that
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% of a cellophane bag---------------> has a 0.60 kg of candy
100%-----------------------------------------> X
X=100*0.60/25--------> X=2.4 kg

the answer is
2.4 kg

the answer in Spanish

Sabemos que
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% de la bolsa de celofan---------------> se llena con 0.60 kg de dulces
100% de la bolsa----------------------------------------->se llenara con X kg
X=100*0.60/25--------> X=2.4 kg

La respuesta es
2.4 kg

5 0

3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$