Answer:
15 games.
Step-by-step explanation:
Here is the complete question: The admission fee to a video game arcade is $1.25 per person, and it costs $0.50 for each game played. Latoya and donnetta have total $10.00 to spend. What is the greatest number of games they will be able to play?
Given: Admission fees= $1.25 per person.
Cost of each game played= $0.50.
Total Money, Latoya and Donnetta have is $10.
First lets find total admission fees both will pay.
∴ Total addmission fees= ![Fees\ per\ person \times number\ of\ person](https://tex.z-dn.net/?f=Fees%5C%20per%5C%20person%20%5Ctimes%20number%5C%20of%5C%20person)
Total addmission fees= ![\$1.25\times 2= \$ 2.50](https://tex.z-dn.net/?f=%5C%241.25%5Ctimes%202%3D%20%5C%24%202.50)
Now, money remaining after paying admission fees.
Money remaining = ![Total\ money - Admission\ fees](https://tex.z-dn.net/?f=Total%5C%20money%20-%20Admission%5C%20fees)
∴ Money remaining = ![\$10-\$2.5= \$ 7.5](https://tex.z-dn.net/?f=%5C%2410-%5C%242.5%3D%20%5C%24%207.5)
∴ Money remained to play video games is $7.5.
Next, finding the maximum number of games, both will be able to play.
As we know, each game will cost $0.50.
Total number of games played= ![\frac{Money\ remaining}{Cost\ of\ each\ game}](https://tex.z-dn.net/?f=%5Cfrac%7BMoney%5C%20remaining%7D%7BCost%5C%20of%5C%20each%5C%20game%7D)
⇒ Total number of games played=![\frac{\$ 7.5}{\$ 0.5} = 15\ games](https://tex.z-dn.net/?f=%5Cfrac%7B%5C%24%207.5%7D%7B%5C%24%200.5%7D%20%3D%2015%5C%20games)
∴ 15 games is the maximum number of games they will be able to play.