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katen-ka-za [31]
3 years ago
12

What is 4/56 plus 356 in fractions

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0
Hi there!

356 + 4/56 = 356 4/56. 

Since a fraction as a mixed number is just the base number plus the fraction itself, this would be the answer. 

Hope this helps!
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Your friend evaluates the expression when m = 10. is your friend correct? Explain your reasoning.
trapecia [35]

Answer:

yes

Step-by-step explanation:

3 * 10 (m) = 30 so 30 - 6 = 24. 3(10) - 6 is basically the same thing just written different, so it equals 24 too. 3(4) just means 3 times 4 ,which equals 13. Hope that made sense lol

7 0
3 years ago
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Explain how you could mentally find 8 x 45 by using the distributive property
dangina [55]
First, break up 45 into 40 and 5 then multipy 8(40) which equals 320 and multipy 8(5) which equals 40. Thrn add 320+40 to get the product 360.
Hope this helped

8x45
8(40)+8(5)
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360
6 0
4 years ago
Twenty percent of 150 is
Svetlanka [38]
20% of 150 is 30 

Change the percentage into a decimal by dividing it over 100:

20 / 100 = 0.2

Multiply:

0.2 × 150 = 30
6 0
3 years ago
X 2 −3x−10=x, squared, minus, 3, x, minus, 10, equals
Andreyy89

Step-by-step explanation:

my brain couldn't comprehend can u write it down for me real quick like the way it's supposed to be written please

5 0
3 years ago
Please Help! This is a trigonometry question.
liraira [26]
\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}


\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}

\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}

________


\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}

________


\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}

\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237


\large\textsf{I hope it helps.}


Tags: <em>trigonometry trig function cosecant csc double angle identity geometry</em>

</span>
8 0
4 years ago
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