Find the volume of a cube with side length of 7 in.
1 answer:
You might be interested in
If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
Answer:
Not a right triangle
Step-by-step explanation:
We can figure out if it is a right triangle or not by using the pythagorean theorem.
a^2 + b^2 = c^2
In this case a and b are 16 and 18
In order for it to be a right triangle, c has to equal 34, in this problem.
16^2 + 18^2 = c^2
= 580^2
= = 24.0832
Since 24.0832 does not equal 34, this is not a right triangle