Answer:
The sum of the measures of the angles of a convex quadrilateral is 360° as a convex quadrilateral is made of two triangles. Yes, this property also holds true for a quadrilateral which is not convex. This is because any quadrilateral can be divided into two triangles.
The answer is <span>SAS (side, angle, side) SAS stands for "side, angle, side" and means that we have two </span>triangles<span> where we </span>know<span> two sides and the included angle are equal. If two sides and the included angle of one </span>triangle<span> are equal to the corresponding sides and angle of another </span>triangle, thetriangles<span> are </span>congruent<span>.</span>
Answer:


Step-by-step explanation:
Let the width of a rectangular garden be 'w'
Length of a rectangular garden = 6 + w
Perimeter of a rectangular garden = 32 feet
<u>
</u><u> </u><u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u> :



Like terms are those which have the same base













Width of a rectangular garden = 5 feet
<u>Substituting </u><u>/</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>w </u><u>in </u><u>6</u><u> </u><u>+</u><u> </u><u>w </u><u>in </u><u>order </u><u>to </u><u>find</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular </u><u>garden</u>

<u>Finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having</u> <u>length of 11 feet and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>feet</u> :



Area of a rectangular garden = 55 ft²
Hope I helped!
Best regards! :D
~
Answer:
x∈(20/3;26/3)
Step-by-step explanation:
12 < 2x-4/3 < 16
first we add 4/3 to each side
12+4/3<2x<16+4/3
we bring to the same denominator
12*3/3+4/3<2x<16*3/3+4/3
(36+4)/3<2x<(48+4/3)
40/3<2x<52/3
now we divide by 2
20/3<x<26/3
x∈(20/3;26/3)
In the table and chart, we have let x represent numbers of Rock CDs and y represent numbers of Rap CDs.
a) The purple dots represent feasible solutions. Their coordinates are listed in the table (for coordinates on the lines) and as a list of points (for points between the lines).
b) The feasible region for total time in hours is shaded blue.
c) The feasible regiion for total cost is shaded red.
d) The overlap of the two regions is shaded purple. The combinations that are feasible are purple dots in that region.
e) The equations used are listed at the left side of the chart. The equations are labeled by color. (≤112 is the cost equation; ≥75 is the hours equation)
ea) The area that is feasible with respect to both constraints is doubly-shaded.
eba) Too much money is spent to the right of the red line.
ebb) Too few hours are used to the left of the blue line.
f) The line for the desired profit is parallel to the "hours" line, but has x-intercept 10 and y-intercept 6. All the points shown except the two on the lower line will give the desired profit.
g) The higher profit line goes through the points (3, 7) and (8, 4). Those two combinations and the points on or near the upper line above y=4 will meet the higher profit requirement.