Precalculus Homework help please.
1 answer:
Answer:
see explanation
Step-by-step explanation:
(5)
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x
Given
3sin²Θ + 2cos²Θ - 2
= 3sin²Θ + 2(1 - sin²Θ) - 2
= 3sin²Θ + 2 - 2sin²Θ - 2
= sin²Θ
(6)
Using the trigonometric identity
secx =
Consider the left side
=
= = secx = right side ⇒ verified
(7)
Using the trigonometric identity
1 + cot²x = csc²x
Given
sin²x. cot²x + sin²x ← factor out sin²x from each term
= sin²x(cot²x + 1)
= sin²x. csc²x
= sin²x × = 1
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Answer:
Explained and written below.
Step-by-step explanation:
(1) Define the decision variables.
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