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stich3 [128]
3 years ago
15

What is the probability of throwing a total score of 10 or less with two dice?​

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

hope it helps

please mark Brainliest

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Which expression is equivalent to log Subscript 12 Baseline StartFraction x Superscript 4 Baseline StartRoot x cubed minus 2 End
Elis [28]

Answer: 4logw (x^{2} - 6) - 1/3logw (x^{2} + 8)

Step-by-step explanation:

5 0
3 years ago
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Please help me if you can. Please also write how you got the answer thank you.
babunello [35]

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

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For question 10, it states \frac{1}{4}. This can be split into \frac{3}{x} and \frac{3}{x} . When x is 12 in the first equation then \frac{3}{12} = \frac{1}{4} and when x is 6 in the second equation \frac{3}{6} =0.5 (0.5 is also  \frac{1}{2}). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11  or  5 whole numbers.

4 0
3 years ago
You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Y
Luda [366]

Answer:

T = 4.541

Step-by-step explanation:

We don't have the standard deviation for the population, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 4.541

6 0
3 years ago
Si una galleta de chocolate aporta un aproximado de 150 kcal y un viaje en bicicleta se quema por media hora se que mas 340 kcal
Elanso [62]

Answer:

Una persona necesitará 2 horas y 30 minutos de viaje en bicicleta para quemar el contenido kilocalórico de cinco galletas.

Step-by-step explanation:

De acuerdo con este problema, la cantidad de calorías que se quema es directamente proporcional al tiempo de viaje en bicicleta. Si sabemos que una galleta aporta 150 kilocalorías, entonces 5 galletas equivalen a 750 kilocalorías.

Por regla de tres simple calculamos el tiempo requerido para quemar 750 kilocalorías:

x = 30\,min \times \frac{750\,kcal}{150\,kcal}

x = 150\,min

Es decir, una persona necesitará 2 horas y 30 minutos de viaje en bicicleta para quemar el contenido kilocalórico de cinco galletas.

6 0
2 years ago
In the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
Vanyuwa [196]
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
7 0
3 years ago
Read 2 more answers
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