Answer:
I would say about 7 feet and 1 inch
Step-by-step explanation:
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
I don't know where the angle β is, so I will make the assumption that tanβ = h/r
V volume = 60
r radius = 2
h = r tanβ
There are two ways you can do this. You can use the longer way:
15+16+17+18+19+20+21+22+23+24 = 195 (starting from the top row, which has 15 logs, up until the bottom row, which has 24 logs, on condition that each second row has one log more than the previous one)
You can also use the formula (where n is the number of rows)
x= (n(first term+last term))/2
x= (10(15+24))/2
x= (10*39)/2
x=390/2
x=195
Either way, there are 195 logs in the stack.
Answer: 4m
Step-by-step explanation:
Note : midpoints divide a line into two equal parts.
To calculate the length of SA;
We can consider the large triangle QRS with
Two midpoints :
A on the line QS, QA = 4m ;
and B on the line RS with RB = 3m
Fron the definition of midpoint :
QS = QA + AS
where QA = AS
QS = 2QA = 2AS
Therefore,
QA = QS
4m = 4m
