Question

WILL GIVE BRANLIEST! please!

Answer 1

Answer:  

Part A:  The function  $f(x)$ has greater slope than function $g(x)$

Part B:  $g(x)$ has a greater y-intercept than $f(x)$.

Step-by-step explanation:

Part A:

For finding the slope of $f(x)$, first we need to pick any two order pairs from the given table in form of $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ and then use the formula of slope:  $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Lets choose two points as $(-1, -15)$ and $(0, -10)$

So,  $m= \frac{-10-(-15)}{0-(-1)}= \frac{-10+15}{0+1}= 5$

Thus, the slope of the function $f(x)$ is 5.

Another function is:  $g(x)=2x+8$

The function $g(x)$ is given in standard slope intercept form $y= mx+b$. So, we will get  $m=2$

Thus, the slope of the function $g(x)$ is 2.

So, the function  $f(x)$ has greater slope than function $g(x)$

Part B:

For function $f(x)$, there is one ordered pair as $(0, -10)$. This point is lying on the y-axis. So, the y-intercept of $f(x)$ is -10.

Now, in $y= mx+b$ form, $'b'$ is represented as the y-intercept. So, for function $g(x)=2x+8$, the value of $'b'$ will be 8.

Thus, the y-intercept of $g(x)$ is 8.

As  $8>-10$,

So, $g(x)$ has a greater y-intercept than $f(x)$.