Recall that
![1+\tan^2x=\sec^2x\implies\sec x=\sqrt{1+\tan^2x}](https://tex.z-dn.net/?f=1%2B%5Ctan%5E2x%3D%5Csec%5E2x%5Cimplies%5Csec%20x%3D%5Csqrt%7B1%2B%5Ctan%5E2x%7D)
We know to take the positive root here because
, which means
as well. Then
![\sec x=\sqrt{1+3^2}=\sqrt4=2\implies\cos x=\dfrac12](https://tex.z-dn.net/?f=%5Csec%20x%3D%5Csqrt%7B1%2B3%5E2%7D%3D%5Csqrt4%3D2%5Cimplies%5Ccos%20x%3D%5Cdfrac12)
We then have
![\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\sin x}{\frac12}=3\implies\sin x=\dfrac32\implies\sec x=\dfrac23](https://tex.z-dn.net/?f=%5Ctan%20x%3D%5Cdfrac%7B%5Csin%20x%7D%7B%5Ccos%20x%7D%3D%5Cdfrac%7B%5Csin%20x%7D%7B%5Cfrac12%7D%3D3%5Cimplies%5Csin%20x%3D%5Cdfrac32%5Cimplies%5Csec%20x%3D%5Cdfrac23)
Answer:
Like this?
Step-by-step explanation:
Negative -247.43, -5 and -1
Positive 247.43, 5 and 1
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Answer:
19/64
Step-by-step explanation:
It cannot be reduced.
Answer
y-16=x^2
Y = 4x +16
4x = y-16
x = (y-16)/4
Slope of that line would be
(0-6)/(3-0) = (-6)/3 = -2
then slope intercept form is
y = mx + b
where m = slope and b is the y intercept
so now we have y = -2x + b
and the y intercept is when x = 0
so b = 6 from that point (0,6)
so we have the equation
y = -2x + 6
which is option C