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irakobra [83]
3 years ago
11

Can someone plz help? Geometry ‼️

Mathematics
2 answers:
Lilit [14]3 years ago
5 0

Answer:

16

Step-by-step explanation:

Mars2501 [29]3 years ago
4 0
The answer to your question is 16
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A billboard is 27 feet high and casts a 36-foot shadow at noon. At the same time, a fir tree next to the billboard casts a 48-fo
Archy [21]

Proportion can be used to find the height = 0.75

Step-by-step explanation:

A billboard is 27 feet high and casts a 36-foot shadow at noon.

Height of billboard = 27 feet

Height of shadow of billboard = 36 feet

\frac{\texttt{Height of billboard}}{\texttt{Height of shadow of billboard}}=\frac{27}{36}\\\\\frac{\texttt{Height of billboard}}{\texttt{Height of shadow of billboard}}=\frac{3}{4}=0.75

A fir tree next to the billboard casts a 48-foot shadow.

Height of shadow of fir tree  = 48 foot

\texttt{Height of shadow of fir tree, H = }\frac{\texttt{Height of billboard}}{\texttt{Height of shadow of billboard}}\times 48

Proportion can be used to find the height = 0.75

5 0
3 years ago
This is for a mastery
valkas [14]

Answer:b

Step-by-step explanation:

3 0
3 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
3 years ago
2/6, 2/4, 2/10 please help with my with this like hurry when you see this pleaseeeee​
Vikentia [17]

Answer:

Step-by-step explanation:

I’m not sure if u mean dividing but this is dividing..2/6=3 2/4=2 2/10=5

5 0
3 years ago
WHY ARE ALL THE ANSWER WRONG!!
Travka [436]

Answer:

is there supposed to be a picture? or something you need help with?

Step-by-step explanation:

6 0
3 years ago
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