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erma4kov [3.2K]
3 years ago
10

Hey can you please help me posted picture of question

Mathematics
2 answers:
Shalnov [3]3 years ago
7 0
Answer:
x³ - 3x² - 18x

Explanation:
Before we begin, remember the following:
xᵃ * xᵇ = xᵃ⁺ᵇ

Now, for the given:
To solve thus question, we will simply multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final answer.

This can be done as follows:
(x + 3)(x² - 6x)
x(x²) + x(-6x) + 3(x²) + 3(-6x)
x³ - 6x² + 3x² - 18x
x³ - 3x² - 18x

Hope this helps :)
Daniel [21]3 years ago
6 0
Hey there :)

( x + 3 )( x² - 6x )

Now, we know what the FOIL method is:
First terms Outer terms Inner terms Last terms
We multiply as the method's full form clearly states

( x )( x² ) + x ( - 6x ) + 3 ( x² ) + 3 ( - 6x )
     ↓               ↓               ↓             ↓
  First         Outer       Inner        Last

x³ - 6x² + 3x² - 18x

Combine any like terms
x³ - 3x² - 18x

Your answer will be \boxed {Option \ A }
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Suppose the daily customer volume at a call center has a normal distribution with mean 5,500 and standard deviation 1,000. What
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Answer:

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 5,500 and standard deviation 1,000.

This means that \mu = 5500, \sigma = 1000

What is the probability that the call center will get between 4,800 and 5,000 calls in a day?

This is the p-value of Z when X = 5000 subtracted by the p-value of Z when X = 4800. So

X = 5000

Z = \frac{X - \mu}{\sigma}

Z = \frac{5000 - 5500}{1000}

Z = -0.5

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Z = -0.7 has a p-value of 0.2420.

0.3085 - 0.2420 = 0.0665

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

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2 years ago
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3 * 8 24

5 * 3 15
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II. Angle C cannot be a right angle.

III. Angle C could be less than 45 degrees.

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