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mario62 [17]
3 years ago
15

A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio

n. the local elementary school is directly to the west of the helicopter at a 62° angle of depression. the distance between the high school and the elementary school is 5 miles. find the distance from the helicopter to the high school. round your answer to the nearest tenth of a mile.
Mathematics
2 answers:
sasho [114]3 years ago
7 0

Answer:

on usatestprep its 1.7

Step-by-step explanation:

guapka [62]3 years ago
5 0
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
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irina1246 [14]

Answer:

The correct options are;

B) The mean and median for the security company are both lower than the mean and the median for the collections performed by other companies

B) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees

Step-by-step explanation:

We use the acronym SC for the security company and OC for the other company

SC OC

1.6 1.5

1.8 2.1

1.6 1.9

1.8 2.2

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1.2 1.7

1.1 2.1

1.2 2.2

1.2 2.2

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The mean is given by  ∑x/n

n = 10

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The median is the \frac{n + 1}{n} th  \ term

Hence

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Median 1.55         2

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b) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees.

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LuckyWell [14K]

Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

          Jeremy can spend no more than $105

Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

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We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

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lakkis [162]

Answer:

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Step-by-step explanation:

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