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Korolek [52]
3 years ago
5

Stiind ca triunghiurile sunt asemenea.calculati lungimile laturilor indicate x=? y=?

Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

x = 8, y = 1

Step-by-step explanation:

Given that the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{4}{y} = \frac{4}{1} ( cross- multiply )

4y = 4 ( divide both sides by 4 )

y = 1

Also

\frac{x}{2} = \frac{4}{1} ( cross-  multiply )

x = 8

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write a division problem involving the the division of a decimal by a whole number with an estimated quotient of 7. Plz help!!!
Contact [7]
14.4÷2~7. You can estimate 14.4 as 14 and simply divide by 2. The goal of estimating is to be able to do an educated guess mentally
8 0
3 years ago
Evaluate the expression 3mn if m=3 and n=7 please help me solve this problem and explain
Vinil7 [7]
Substitute 3 into the expression for m, and 7 into it for n. So 3mn = 3(3)(7) = 3 x 21 = 63.
6 0
3 years ago
Read 2 more answers
Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch
Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30  (3).

Writing equations (1) and (3) in matrix form, we have

\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]

Using Cramer's rule to solve for x and y,

x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0
3 years ago
Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
Natalka [10]
y = 360(1.03)x is the answer
6 0
3 years ago
Read 2 more answers
How do you solve it?
Elis [28]

At heart we're being asked for a line through two points,


(40^\circ \textrm{ C}, 355 \textrm { m/s}) \quad \textrm{and} \quad (49^\circ \textrm{ C}, 360 \textrm { m/s})


In general the line through (a,b) and (c,d) is


(y-b)(c-a)=(x-a)(d-b)


Check that you understand why both (a,b) and (c,d) are on this line.


Here our indepedent variable, instead of x, is T, temperature. Our dependent variable is v, velocity. Substituting,


(v - 355)(49 - 40) = (T - 40)(360 - 355)


9(v - 355) = 5(T - 40)


v-355 = \frac 5 9 T - \frac{200}{9}


v= \frac 5 9 T - \frac{200}{9} + 355


v= \frac 5 9 T + \frac{2995}{9}


That's our answer; let's check it.


When T=40, v = (5/9)40 + (2995/9) = 355 good


When T=49, v= (5/9)49 + (2995/9) = 360 good




7 0
3 years ago
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