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3 years ago

Stiind ca triunghiurile sunt asemenea.calculati lungimile laturilor indicate x=? y=?

Mathematics

1 answer:

Fantom [35]3 years ago

7 0

Answer:

x = 8, y = 1

Step-by-step explanation:

Given that the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{4}{y}$ = $\frac{4}{1}$ ( cross- multiply )

4y = 4 ( divide both sides by 4 )

y = 1

Also

$\frac{x}{2}$ = $\frac{4}{1}$ ( cross- multiply )

x = 8

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Select three unit rates that can be used To describe the price of juice one dollar for 12 ounces $1.59 for a pint two dollars fo

enot [183]

Answer:

$1.59 for a pint,

two dollars for a quart,

299 for a gallon

Step-by-step explanation:

Since, rate is used to compare different kinds of quantities and it is the ratio of the quantities,

Also, unit rate states the amount of first quantity corresponding to the unit amount of second quantity,

When we talk about the unit rates for a quantity,

Then it shows the price of the quantity per unit amount.

Thus, by the above explanation it is clear that,

The unit price for representing the price of juice would be,

$1.59 for a pint,

two dollars for a quart,

299 for a gallon.

Note : we do not consider 'one dollar for 12 ounces' a unit price because it is not the price per 1 ounce.

7 0

3 years ago

If h(y)=3y^2-2y+5, find the value of h(-2)

Galina-37 [17]

Answer:

Step-by-step explanation:

h(y)=3y^2-2y+5

Let y = -2

h(y)=3(-2)^2-2(-2)+5

= 3(4) +4 +5

= 12 +4 +5

=21

6 0

3 years ago

an inverted cone has a height of 11 inches and an initial radius of 18 inches. the volume of the inverted cone is decreasing at

joja [24]

Radius of cone is decreasing at the rate of $\frac{1623}{110\pi}$ inches

What is rate of change?

Suppose there is a function and there are two quantities. If one quantity of a function changes, the rate at which other quantity of the function changes is called rate of change of a function.

Here rate of change of radius of cone has been calculated

Radius of cone = 18 inches

Height of cone = 11 inches

Volume of cone (V) = $\frac{1}{3} \pi r^2h$

$\frac{dV}{dt} = \frac{1}{3} \pi h (2r\frac{dr}{dt})\\-541 = \frac{2}{3} \pi \times 11\times 5\times\frac{dr}{dt}\\\frac{dr}{dt} = -\frac{541 \times 3}{2 \times \pi \times 11 \times 5}\\\frac{dr}{dt} = -\frac{1623}{110 \pi}$