Answer:
In arithmetic, variables look like letters.
Step-by-step explanation:
As we know that Mathematical arithmetic deals with numbers and certain properties with them.
Some of the main properties between numbers are as follows:
Variables do not remain constant, so we basically assign a number to a variable with an equal operator denoted by '='.
For example, let us assume a variable x being equal to 7. so it can written as:

Let suppose the value of the variable x=7 changes to x=10, then the new value will be:

Therefore, the correct answer is:
In arithmetic, variables look like letters.
Answer:
Step-by-step explanation:
You must use common denominators so you convert them with common facts that are used for 9 & 5 so I used 9 & 5 for each other
4*5=20
9*5=45 giving the new fraction of 20/45 for clothes
1*9=9
5*9=45 giving a new fraction of 9/45
Then subtract food from clothing cost to get an answer
20/45 - 9/45 = 11/45 more on clothes than food
Answer:
- A: 24,500
- B: 11,800
- C: 12,700
Step-by-step explanation:
Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.
The revenue from those seats is, ...
24,500×$30 = $735,000
so the revenue from B and C seats is ...
$1,246,800 -735,000 = $511,800
__
We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...
24b +18(24500-b) = 511800
6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms
b = 70,800/6 = 11,800 . . . . . . . seats in B section
24,500 -11,800 = 12,700 . . . . . seats in C section
There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.
6(100+90+8) is the equation
6x100 =600
6x90 =540
6x8 = 48
1,188 is the answer
Step-by-step explanation:
a. lim(x→2) [g(x) + h(x)]
Use additive property of limits.
= lim(x→2) g(x) + lim(x→2) h(x)
= 0 + 5
= 5
b. lim(x→2) [3 h(x)]
Use multiplication property of limits.
= [lim(x→2) 3] [lim(x→2) h(x)]
= 3 lim(x→2) h(x)
= 3 (5)
= 15
c. lim(x→2) [g(x) h(x)]
Use multiplication property of limits.
= [lim(x→2) g(x)] [lim(x→2) h(x)]
= (0) (5)
= 0