Answer:
question 19
(2x-5)(3x+1)
Step-by-step explanation:
question 19
6x^2-13x-5
6x^2 coefficient = 6
-13x coeddicient = -13
-5 is constant
multiply coefficient of first term by the constant
i.e. 6*-5= -30
get 2 factors of -30 whoose sum equals -13
-15 +2 = -13
rewrite to have
6x^2-15x+2x-5
3x(2x-5) the firs term
1(2x-5)
add up,
(3x+1)(2x-5)
Answer:
20 students
Step-by-step explanation:
If the class decreased by 15%, the students that she has now (17) represents a percentaje of:
100% - 15% = 85%
so<u> the 17 students are 85% of what she had</u>:
Students Percentage
17 ⇒ 85%
and we are looking for how many students she had 2 years ago, thus we are looking for the <u>100%</u> of students (the original number of studens). If we represent this number by x:
Students Percentage
17 ⇒ 85%
x ⇒ 100%
and we solve this problem using the <u>rule of three</u>: multiply the cross quantities on the table( 17 and 100) and then divide by the remaining amount (85):
x = 17*100/85
x = 1700/85
x=20
2 years ago she had 20 students
N-3+6
i dot believe that is the correct answer have an amazing day love ;)
