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777dan777 [17]
3 years ago
11

Estimate the area of a circle. use 22/7 for pi

Mathematics
2 answers:
olganol [36]3 years ago
5 0
If the radius is r,
area of circle= pi x r^2

=22r^2 / 7 
tatyana61 [14]3 years ago
5 0

Answer:

196 x 3.14 = 615.44

Step-by-step explanation:

You might be interested in
What is the side length, in inches, of the pets
tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is 4x-5 inches

Step-by-step explanation:

Given

Area of the square of design = 16x^{2} -40x+25

First we find the roots of equation 16x^{2} -40x+25=0

The roots of the quadratic equation ax^{2} +bx^{2} +c=0 are given by

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a=16, b=-40, c=25

x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}

x=\frac{40\pm\sqrt{1600-1600}}{32}

x=\frac{40\pm\sqrt{0}}{32}

x=\frac{40}{32}

x=\frac{5}{4}

4x=5\\4x-5=0

That is, the factors of the polynomial 16x^{2} -40x+25 are 4x-5 and 4x-5.

So, Area of the square design = 16x^{2} -40x+25 = (4x-5)^{2}

Area of a square = Length^2

Thus, the length of the sign is 4x-5 inches

7 0
3 years ago
HELP ASAP PLEASE 3 extra points if you get it right
-BARSIC- [3]
It would be the origin
8 0
3 years ago
Read 2 more answers
Help!!! I really need this
anyanavicka [17]

Answer:

bruh

Step-by-step explanation:

maybe google works

6 0
2 years ago
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
2 years ago
How to solve y=3(0)^2-6(0)-5
Ilya [14]
Y = - 5 

I hope this helps. :)
8 0
3 years ago
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