Can someone answer this ASAP please

If f(x) = 3x22, evaluate afI: ()k=1

Korolek [52]

Step 1: Write out the function given

$f(x)=3x^2-x$

Step 2: Interprete the question given

$\sum ^5_{k\mathop=1}f(\frac{k}{2})$

The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5

Step 3: Find the expression for f(k/2)

$\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}$ $\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}$

Hence, the answer is 33.75

5 0

9 months ago

Which units should she use to report the distance from the earth to the moon?

Anvisha [2.4K]

Well,

The distance from the earth to the moon, FYI, is over 200,000 miles. That is a LONG distance. We are trying to find a reasonable unit of measurement.

What do we mean by "reasonable?" We mean that that unit should be able to express the distance as a number that is not huge or tiny. In other words, we want it to be as close as possible to 1.

mm, or millimeters, is a tiny unit. It is not reasonable.

cm, or centimeters, is also a tiny unit. It also is not reasonable.

m, or meters, is also a relatively small unit. It also is not reasonable.

km, or kilometers, is the largest of the four. In km, the distance from the earth to the moon is about 363,000 km. That's not too bad.

However, if these weren't the only options, I would choose Mm, or megameters, which would put the distance at 363 Mm.

The correct option is D.

7 0

2 years ago

For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.

Yakvenalex [24]

Answer:

$Sd(X) =\sqrt{1.2}=1.095$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=5, p=0.4)$