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Amanda [17]
3 years ago
7

Suppose you are studying a population with the following characteristics: Birth rate = 14 per 1,000/year Death rate = 6 per 1,00

0/year Immigration rate = 5 per 1,000/year Emigration rate = 1 per 1,000/year What is the growth rate for this population?
Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

 12 per 1,000 / year would be population growth

Step-by-step explanation:

To know the population growth it is important to know what it contributes to its growth and that it decreases it.

Birth rate ==> increases growth

Death rate ==> decreases growth

Immigration rate ==> increases growth

Emigration rate ==> decreases growth

Now it only remains to add those that increase growth and subtract those that decrease, like this:

 14 per 1,000 / year - 6 per 1,000 / year + 5 per 1,000 / year - 1 per 1,000 / year = 12 per 1,000 / year

 12 per 1,000 / year would be population growth

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Computing growth rates (I): Suppose Xt=(1.04)^t and Yt=(1.02)^tCalculate the growth rate of Zt in each of the following cases:(a
Doss [256]

Answer:

z(t) = (0.9808)^t

z(t) = (1.0196)^t

z(t) = (0.9808)^t

z(t) = (1.03)^t

z(t) = (1.0404)^t

z(t) = (1.0001)^t

Step-by-step explanation:

We are given the following in the question:

x(t)=(1.04)^t\\y(t)t=(1.02)^t

We have to find the growth rate z(t) in each of the following cases:

(a) z = xy

z(t) = x(t)y(t)\\z(t) = (1.04)^t.(1.02)^t\\z(t) = (1.04\times 1.02)^t\\z(t) = (1.0608)^t

(b) z=x/y

z(t) =\displaystyle\frac{x(t)}{y(t)}\\\\z(t) = \frac{(1.04)^t}{(1.02)^t} = \bigg(\frac{1.04}{1.02}\bigg)^t\\\\z(t) = (1.0196)^t

(c) z=y/x

z(t) =\displaystyle\frac{y(t)}{x(t)}\\\\z(t) = \frac{(1.02)^t}{(1.04)^t} = \bigg(\frac{1.02}{1.04}\bigg)^t\\\\z(t) = (0.9808)^t

(d) z=x^(1/2) y^(1/2)

z(t) = (x(t))^{\frac{1}{2}}(y(t))^{\frac{1}{2}}\\z(t) = ((1.04)^t)^\frac{1}{2} ((1.02)^t)^\frac{1}{2}\\z(t) = (1.0608)^{\frac{t}{2}}\\z(t) = (1.03)^t

(e) z=(x/y)^2

z(t) =\bigg(\displaystyle\frac{x(t)}{y(t)}\bigg)^2\\\\z(t) =\bigg( \frac{(1.04)^t}{(1.02)^t}\bigg)^2 = \bigg(\frac{1.04}{1.02}\bigg)^{2t}\\\\z(t) = (1.0404)^t

(f) z=x^(-1/3)y^(2/3)

z(t) = (x(t))^{\frac{-1}{3}}(y(t))^{\frac{2}{3}}\\z(t) = ((1.04)^t)^{\frac{-1}{3}}((1.02)^t)^{\frac{2}{3}}\\z(t) = ((1.04)^{\frac{-1}{3}})^t((1.02)^{\frac{2}{3}})^t\\z(t) = (1.04^{\frac{-1}{3}}\times 1.02^{\frac{2}{3}})^t\\z(t) = (1.0001)^t

5 0
3 years ago
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