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2 years ago

the length of an object is measured as 95.7 centimeters. what is this measurement in scientific notation?

1 answer:

7 0

In scientific notation, you want a number between 1 and 10; so the answer is <u>9.57 x 10</u> (to the understood first power).

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Find the number of degrees in the third angle of the triangle.<br> 100 degree and 49 degrees

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Step-by-step explanation:

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2 years ago

Nasir has an annual salary of 64,000 and his company pays him twice a month. What is the gross income per paycheck that Nasir re

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64,000/2=32,000

32,000/12= $2,666.67 per paycheck

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3 years ago

The number line below represents 1 kilometer. What part of the number line represents 6/8 kilometer?

Nikitich [7]

Answer:

Step-by-step explanation:

You have -5 1/2 to find the complete opposite all you have to do is take away the negative sign and find the number on the number line.

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2 years ago

PLEAS HELP ME OUT !!!!!!

Kamila [148]

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Step-by-step explanation:

the number line is patterned in twos, so the dot will be at 20, since its 4 spaces away from 12

3 0

1 year ago

Read 2 more answers

Consider f and c below. f(x, y, z) = yzexzi + exzj + xyexzk,

Jet001 [13]

Answer:

$f(x,y,z)=ye^{xz}+C$

Step-by-step explanation:

We can write the given expression as :

$\vec f(x,y,z)=yze^{xz}\,\vec\imath+e^{xz}\,\vec\jmath+xye^{xz}\,\vec k$

As given, f = ∇f.

∇f = $\dfrac{\partial f}{\partial x}i$ + $\dfrac{\partial f}{\partial y}j$ + $\dfrac{\partial f}{\partial z}k$

We can write the partial derivative with respect to x, y and z.

$\dfrac{\partial f}{\partial x}=yze^{xz}$ ___(Equation 1)

$\dfrac{\partial f}{\partial y}=e^{xz}$ ______(Equation 2)

$\dfrac{\partial f}{\partial z}=xye^{xz}$ ______(Equation 3)

Take equation 2 and integrate with respect to y,

$\dfrac{\partial f}{\partial y}=e^{xz}$

$f(x,y,z)=ye^{xz}+a(x,z)$ ----------Equation 4

Derivate both sides w.r.t x , we get :

$\frac{d}{dx}(yze^{xz})=yze^{xz}+\dfrac{\partial a}{\partial x}$

$\dfrac{\partial a}{\partial x}=0$

integrate

a(x,z)=b(z)

put in equation 4 ,

we get :

$f(x,y,z)=ye^{xz}+b(z)$

take derivative wrt z

$\frac{d}{dz} (ye^{xz}+b(z))\impliesxye^{xz}=xye^{xz}+\frac{db}{dz}$

we can take here:

$\frac{db}{dz} = 0$

integrate:

$\int\ {\frac{db}{dz} } \, =\int0$

b(z) = C

The function can be written as :

from equation 4 :

$f(x,y,z)=ye^{xz}+C$

Where C is a constant.

4 0

2 years ago