No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
Answer:
-0.7
Step-by-step explanation:
You can choose any digits you wish for 
and 
but the difference must be 0.7. I chose 1.0 and 0.3.
This equation is in slope-intercept form; y = mx+b.
m is the slope and b is the y-intercept, so to find the slope you'd look at the coefficient of x.
In this equation, y = 3x+5, the coefficient of x is 3, so that means that the slope of this equation is 3.
Answer is:
3 is the slope
For example:
x+2y=7
6x+7y=2
__________
x=7-2y *
6*(7-2y)+7y=2 **
__________
x=7-2y
42-12y+7y=2
__________
x=7-2y
-5y=-40
__________
x=7-2y
y=8
x=-9
