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Olenka [21]
3 years ago
11

Gabriel wants to send a parcel to Italy.

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

Step-by-step explanation:

10+20+40=70

70*0.8=7*10*0.8=56 L (We Deliver)

total area =2*(10+20)*40+2*10*20=2*30*40+400=2400+400=2800 cm^2

2800*0.02=28*100*0.02=28*2=56 L (Go Parcels)

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2 years ago
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1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff
Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If  A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that  f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0
3 years ago
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For 0.1030, the least valuable digit place is the 0.103<u>0</u>. This is because this numeral appears at the end of the string, and is the least valuable.

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2 years ago
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Marizza181 [45]

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3 years ago
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