X=weekly allowance
x/2=money saved (= money spent).
We can suggest this equation:
x/2+4=12
lowest common multiple=2
x+8=24
x=24-8
x=16
Answer: her weekly allowance is $16.
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
It's A. If U=16, 6+10=16
and if you plug in the numbers for the second equation it's 36=2(10)+16
Hey there!
Assuming you meant
If so, follow these steps so it can be a little bit easier to solve
Firstly, we have to 
by 
on each of your sides
We get: 
Now, we have 
by 
on each of your sides
We get: 
± 
Therefore , your answer is: ±
Good luck on your assignment and enjoy your day!
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