So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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Answer:
P = 100
Area = 625
Step-by-step explanation:
Area = s^2
sqrt(area) = sqrt(s^2)
area = 25*25
sqrt(25*25) = sqrt(s^2)
s = 25
P = 4*s
P = 4 * 25
P = 100
Area = s^2
s = 25
Area = 25^2
Area = 625
Answer:
0.25
Step-by-step explanation:
3/12 = 1/4
1÷4= 0.25
