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zhannawk [14.2K]
3 years ago
5

You are getting ready for a family vacation. you decide to download as many movies as possible before leaving for the road trip.

if each movie takes 1 2/5 to download and you downloaded for 5 1/4 fours, how many movies did you download
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
Here is the solution for the given problem above.
Given: 1 2/5 hour = time it takes to download a movie
            5 1/4 hours = total hours for the download
            ? = number of movies downloaded
First, we need to simplify 1 and 2/5 hour, which is 1.4 hour, and 5 1/4 is 5.25 hours. Next, to get the number of movies downloaded, we divide 5.25 by 1.4 and the result is 3.75. Round this off to a whole number and we  get 4. Approximately, you were able to download 4 MOVIES. Hope this helps.
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Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
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\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

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