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Alenkasestr [34]
3 years ago
12

Which expression is equivalent to 3+/- square 32x^8 y^10

Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0
3+/-sqrt(32x^8y^10) = 3+/-4x^4y^5*sqrt(2)!
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9(5r-2) and 14r-7 yes or no to tell if this expression is equivalent or not
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Answer:

No instead of doing multiplication u did division

Step-by-step explanation:

This equation is called distributive property where u multiply the answer from the outside by the inside number

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PLEASE HELP FAST!!! ITS EASY BUT NOT FOR ME!!
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The answer is number 4
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The population of Stark county this year is 7,921 people. Last year the population was 7,547 people. Find the approximate percen
Sholpan [36]

Answer:

Option (C)

Step-by-step explanation:

To determine the population we use the formula,

P_n=P_0(1+r)^{n}

Where P_n = final population

P_0 = Initial population

r = percentage growth

Now we substitute these values in the formula,

7921=7547(1+r)^1

\frac{7921}{7547}=(1+r)

r = 1.0496 - 1

r = 0.0496

r = 0.05

Therefore, percentage growth of the population of Stark county is 5%.

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A restaurant offers a dinner special in which diners can choose anyone of three appetizers, anyone of four entries, anyone of fi
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3 years ago
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
Aleonysh [2.5K]

Answer:

t=5.18 minute

Step-by-step explanation:

Using Newton's law of cooling

\frac{dT}{dt}=-k(T-T_{s})

T is temperature of a cup of coffee at any time t T_{s}, is the temperature of the surrounding and k is a constant of proportionality in this negative because temperature is decreasing.

T(0)=190\\T(1)=170\\T_{s}=66

\frac{dT}{dt}=-k(T-T_{s})\\\frac{dT}{(T-T_{s})}=-k*dt\\\int\limits {\frac{1}{T-T_{s} } } \, dT=-\int\limits {k} \, dt\\ln(T-T_{s})=k*t+C\\e*ln(T-T_{s})=e^{k*t+C} \\T-T_{s}=e^{k*t}*e^{C}\\e^{C}=C\\T-T_{s}=e^{k*t}*C\\T=T_{s}+e^{k*t}*C

To find constant knowing the time and the temperature the first step of the change of energy in cup of coffee

T=T_{s} +e^{-k*t}*C\\ C=190-66=124\\170=66+124*e^{-k*2}\\ 170-66=124*e^{-k*2}\\ln(\frac{104}{124})=ln*e^{-k*2}\\-0.175=-k*2\\k=0.08794

Now using the constant of decreasing can find the time to be a 145 temperature the cup of coffee

145=66+124*e^{-k*t} \\145-66=124*^{-0.087*t}

ln(0.637)=ln*e(-0.087*t)\\-0.45=-0.087*t\\t=5.18minutes

4 0
4 years ago
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