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stepan [7]
3 years ago
12

7 ft x 15ft x 17 ft What kind of triangle

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0

Answer:

It's a scalene triangle

Step-by-step explanation:

victus00 [196]3 years ago
6 0
I think the answer is a scalene triangle
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What is the final balance for the investment?
xxMikexx [17]
$23,152.50

Start: $20,000
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4 years ago
Pls someone help quick
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Step-by-step explanation:

6 0
3 years ago
The square of a negative number is twenty-eight more than three times the negative number. Find the number.
MAXImum [283]
The number is x

it is negative
the square is 28 more than 3 times itself
x²=28+3x
minus (28+3x)
x²-3x-28=0
factor
(x-7)(x+4)=0
set to zero

x-7=0
x=7
this is not the answer because we were told the number was negative


x+4=0
x=-4
correct

the number is -4
test
(-4)²=28+3(-4)
16=28-12
16=16
check


the number is -4
8 0
3 years ago
Read 2 more answers
each day last week, Ms. wilson walked3/4 mile. what is the total distance, in miles, that Ms. Wilson walked in 4 days?
zloy xaker [14]
Hey there! :D

Since she walks 3/4 a mile a day, we can multiply that by 4.

3/4= .75

4*.75= 3

She walked 3 miles in 4 days.

I hope this helps!
~kaikers
6 0
3 years ago
Read 2 more answers
4.
zubka84 [21]

Answer:

See Explanation Below

Step-by-step explanation:

Given

(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx.cos x.

Required

Prove

To start with; we open the bracket on the left hand side

(sin x - cos x)^2 = (sin x - cos x)(sin x - cos x)

(sin x - cos x)^2 = (sin x )(sin x - cos x)- (cos x)(sin x - cos x)

(sin x - cos x)^2 = sin^2 x -sinx cos x - sin xcos x + cos^2 x

(sin x - cos x)^2 = sin^2 x -2sinx cos x + cos^2 x

Reorder

(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x

From trigonometry;

sin^2x + cos^2x = 1

So;

(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x

becomes

(sin x - cos x)^2 = 1 - 2sinx cos x

Also from trigonometry;

sec^2x - tan^2x = 1

So,  

(sin x - cos x)^2 = 1 - 2sinx cos x

becomes

(sin x - cos x)^2 = sec^2x - tan^2x  - 2sinx cos x

Proved

3 0
3 years ago
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