1/2 base by height
Your answer is 6
Answer: OPTION A
Step-by-step explanation:
To simplify the expression you must multiply the numerator and the denominator of the expression by √3.
As all the square roots have equal index, you can multiply the radicands, which are the numbers inside of the sqaures roots.
You also must keep on mind that:
![(\sqrt[n]{a})^n=a](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Ba%7D%29%5En%3Da)
Therefore, you obtain:
![\frac{6\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}=\frac{6\sqrt[]{6}}{3}=\frac{2\sqrt[]{6}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B6%5Csqrt%7B2%7D%2A%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%2A%5Csqrt%7B3%7D%7D%3D%5Cfrac%7B6%5Csqrt%5B%5D%7B6%7D%7D%7B3%7D%3D%5Cfrac%7B2%5Csqrt%5B%5D%7B6%7D%7D%7B3%7D)
Answer:
If I get 0=0 then it means:
- If the system of equations is 2 linear equations in 2 variables, there is infinity number of solutions
- If the system of equations is 3 linear equations in 3 variables, there might be infinite number of solutions
Step-by-step explanation:
Linear equation systems can consist of two or three equations with two or three unknowns respectively.
A system of linear equations in two variables has infinite solutions when the lines made by them overlap each other and similarly a system with three variables has infinite solutions when two lines overlap each other and third plane is parallel to them
Hence,
If I get 0=0 then it means:
- If the system of equations is 2 linear equations in 2 variables, there is infinity number of solutions
- If the system of equations is 3 linear equations in 3 variables, there might be infinite number of solutions
Answer:
STEP
1
:
Equation at the end of step 1
(5r2 - 14r) + 8
Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .
-40 + -1 = -41
-20 + -2 = -22
-10 + -4 = -14 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4
5r2 - 10r - 4r - 8
Step-4 : Add up the first 2 terms, pulling out like factors :
5r • (r-2)
Add up the last 2 terms, pulling out common factors :
4 • (r-2)
Step-5 : Add up the four terms of step 4 :
(5r-4) • (r-2)
Which is the desired factorization
Final result :
(r - 2) • (5r -4)
