Question

Equation to parallel line of y=-6x+2 and passes through (-1,2)

Answer 1

Answer:

y = -6x - 4

Step-by-step explanation:

The equation of a line looks like y = mx + b (general form)

"m" is the slope, how steep the line is.

"b" is the y-intercept, where the graph hits the y-axis.

"x" and "y" are solutions, or points on the line.

(-1, 2) is a point on the line. It's written as an ordered pair like (x, y).

x = -1

y = 2

Parallel lines have the same slope.

In y=-6x+2, the slope is -6 because it's attached to "x", just like in the general form.

m = -6

Substitute the information so far into the general form.

y = mx + b

2 = (-6)(-1) + b

Simplify the multiplication.

2 = 6 + b

Isolate "b" (separate it from everything else).

2 - 6 = 6 - 6 + b              Subtract 6 from both sides

-4 = b                              Y-intercept

b = -4                              Variable on left side for standard formatting

Notice in the example of a line (y=-6x+2), you only need to fill in "m" and "b".

Substitute the values for slope and y-intercept into the general form.

y = -6x - 4                 Equation of the line