I believe the answer is c, TSR
A perpendicular line has a slope of infinity. Therefore it is not possible to write the equation in point-slope form.
The equation is x = -4.
Standard equation: (x-h)^2 + (y-k)^2 = r^2
Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10
Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2
Where are the choices- lololol
Given: p=2, h=8
5p^2=h
5(2)^2=8 ------- substitution here
5(4)=8
20 doesn't equal 8
I did exponents first because it comes before multiplication in the order of opertions.
